A uniform rod of mass 300 g and length 50 cm rotates at a uniform angular speed of 2 rad/s about an axis perpendicular to the rod through an end. Calculate a. the angular momentum of the rod about the axis of rotation b. the speed of the centre of the rod and c. its kinetic energy.

Answer

A, B, C

Explanation

A uniform of rod mass 300 gm and length =50 cm rotates wilth a uniform angular velocity =2 rad/s abut an axis `_|_` to te rod through an end.
a. `L=Iomega`
`I at the end =(mL^2)/3=({0.3xx(0.5)^2})/3`
`=((.3xx0.25))/3`
`=0.075/3=0.025kg-m^2`
Therefore angular momentum about that point
`=0.025xx2`
`-=0.05kg-m^2/s`
b. Sped ofthe centre of rod
`V=omegar=2xx(50/2)`
`=50 cm/s=0.5m/s`
c. It kinetic energy
c. `1/2Iomega^2=(1/2)xx0.025xx2^2`
`=0.05joule