Home
Class 11
PHYSICS
Two particles of masses 1.0 kg and 2.0 k...

Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles.

Text Solution

AI Generated Solution

To solve the problem of finding the initial acceleration of two particles due to their mutual gravitational attraction, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the masses and separation**: - Let mass \( M = 2.0 \, \text{kg} \) (larger mass). - Let mass \( m = 1.0 \, \text{kg} \) (smaller mass). - The separation \( r = 50 \, \text{cm} = 0.5 \, \text{m} \). ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    HC VERMA ENGLISH|Exercise worked out Examples|13 Videos
  • GRAVITATION

    HC VERMA ENGLISH|Exercise Objective -1|16 Videos
  • FRICTION

    HC VERMA ENGLISH|Exercise Questions for short Answer|11 Videos
  • HEAT AND TEMPERATURE

    HC VERMA ENGLISH|Exercise Objective 2|6 Videos

Similar Questions

Explore conceptually related problems

Three particles, each of mass m are fixed at the vertices of an equilateral triangle of side length a . The only forces acting on the particles are their mutual gravitational forces. Then answer the following questions. Force acting on particle C , due to particle A and B

Two particles of masses 1kg and 2kg are located at x=0 and x=3m . Find the position of their centre of mass.

Two particles of masses 1kg and 2kg are located at x=0 and x=3m . Find the position of their centre of mass.

Three particles, each of mass m are fixed at the vertices of an equilateral triangle of side length a . The only forces acting on the particles are their mutual gravitational forces. Then answer the following questions. The gravitational potential at O is

Three particles, each of the mass m are situated at the vertices of an equilateral triangle of side a . The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining the original mutual separation a . Find the initial velocity that should be given to each particle and also the time period of the circular motion. (F=(Gm_(1)m_(2))/(r^(2)))

Three particles, each of the mass m are situated at the vertices of an equilateral triangle of side a . The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining the original mutual separation a . Find the initial velocity that should be given to each particle and also the time period of the circular motion. (F=(Gm_(1)m_(2))/(r^(2)))

Two bodies of masses 1 kg and 6 xx 10^(24) kg are placed with their centres 6.38 xx 10^(6)m apart. Calculate the force of attraction between the two masses. Also find the initial acceleration of the two masses. [Assume that no other forces act on them]

Two particles of masses 2m and 3m are placed at separation d on a smooth surface. They move towards each other due to mutual attractive force. Find (a) acceleration of c.m. (b) Velocity of c.m. when separation between particles becomes d//3 . ( c) At what distance from the initial position of mass 2m , the particles collide.

Two spherical balls of mass 10 kg each are placed 10 cm apart. Find the gravitational force of attraction between them.

Two small bodies of masses 10 kg and 20 kg are kept a distnce 1.0 m apart and released. Assuming that only mutual gravitational force are acting, find the speeds of the particles when the separation decreases to 0.5 m.

HC VERMA ENGLISH-GRAVITATION-Question for short Answers
  1. Two particles of masses 1.0 kg and 2.0 kg are placed at a separation o...

    Text Solution

    |

  2. Can two particles be in equilibrium under the action of their mutual g...

    Text Solution

    |

  3. If heavier bodies are attracted more strongly by the earth why don't t...

    Text Solution

    |

  4. Can you think of two particles which do not exert gravitational force ...

    Text Solution

    |

  5. The earth revolves round the sun because the sun attracts the erth. Th...

    Text Solution

    |

  6. At noon, the sun and the earth pull theobjects on the earth's surface ...

    Text Solution

    |

  7. An apple fals from a tree. An insect in the apple filnds that the eart...

    Text Solution

    |

  8. Suppose the gravitational portential due to a small system is k/r^2 at...

    Text Solution

    |

  9. The gravitational potential energy of a two particle system is derived...

    Text Solution

    |

  10. The weight of an object is more at the poles than at the equator. Is i...

    Text Solution

    |

  11. The weight of a body at the poles is greater than the weight at the eq...

    Text Solution

    |

  12. If the radius of the earth decreases by 1% without changing its mass, ...

    Text Solution

    |

  13. A nut becomes lose and gets detached from a satellite revolving around...

    Text Solution

    |

  14. Is it necessary for the plane of the orbit of a satellite to pass thr...

    Text Solution

    |

  15. Consider earth satellites in circular orbits. A geostationary satellit...

    Text Solution

    |

  16. No part of India is situated on the equator. Is it possible to have a ...

    Text Solution

    |

  17. As the earth rotates about its axis, a person living in his house at t...

    Text Solution

    |

  18. Two satellites going in equatoral plane have almost same radii. As see...

    Text Solution

    |

  19. A spacecraft consumes more fuel in going from earth to moon than it ta...

    Text Solution

    |