The gravitational field due to a mass distribution is `E=K//x^(3)` in the x - direction. ( K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is

Explanation

To find the gravitational potential \( V(x) \) at a distance \( x \) given the gravitational field \( E = \frac{K}{x^3} \), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Relationship**:
The gravitational potential \( V \) is related to the gravitational field \( E \) by the equation:
\[
E = -\frac{dV}{dx}
...