A body is weighed by a spring balance to be `1000 n` at the north pole. How much will it weight at the equator? Account for the earth's rotation only.

Explanation

Let g' be the acceleration due to gravity at equation and that of pole =g.
`g=omega^2r`
`=9.81-(9.3xx10^-5)xx6400xx10^3`
` =9.81-(53.29xx10^-10)xx64xx10^5`
`=9.81xx0.034=9776m/s^2`
`mg=1kgxx9.776 m/s^2`
`=9.776 N or 0.997 kg`
The body will weigh 0.997 kg at equator.