A copper piece of mass 10 g is suspended by a vertical spring. The spring elongates 1 cm over its natural length to keep the piece in equilibrium. A beaker containing water is now placed below the piece so as to immerse the piece completely in water. Find the elongation of the spring. Density of copper =9000 kgm^-3. `Take g=10ms^-2`

Explanation

To solve the problem step by step, we will analyze the forces acting on the copper piece and calculate the elongation of the spring when the piece is immersed in water.

### Step 1: Understand the Forces Acting on the Copper Piece
When the copper piece is suspended by the spring, two main forces act on it:
- The gravitational force (weight) acting downward, \( F_g = mg \)
- The spring force acting upward, \( F_s = kx \)

Where:
...