A beaker containing a liquid is kept inside a big closed jar. If the air inside the jar is continuously pumped out, the pressure in the liquid near the bottom of the liquid will

Options

A. increase
B. decrease
C. reamin constant
D. first decrease and then increse

Answer

To solve the problem, we need to analyze how the pressure at the bottom of the liquid in the beaker changes when the air inside the closed jar is continuously pumped out.

### Step-by-Step Solution:

1. **Understanding the Setup**:
- We have a beaker filled with liquid placed inside a closed jar.
- The jar is sealed, and air is being pumped out, creating a vacuum.

2. **Pressure at the Surface of the Liquid**:
- Initially, when the jar is filled with air, the pressure at the surface of the liquid (let's denote it as \( P_{\text{atm}} \)) is equal to the atmospheric pressure.
- This pressure exerts a force on the surface of the liquid.

3. **Pressure at the Bottom of the Liquid**:
- The pressure at the bottom of the liquid can be expressed using the hydrostatic pressure formula:
\[ P_{\text{bottom}} = P_{\text{atm}} + \rho g h \]
- Here, \( \rho \) is the density of the liquid, \( g \) is the acceleration due to gravity, and \( h \) is the height of the liquid column.

4. **Effect of Pumping Air Out**:
- As air is pumped out of the jar, the atmospheric pressure \( P_{\text{atm}} \) decreases.
- Since the jar is sealed, the pressure above the liquid decreases, which directly affects the pressure at the bottom of the liquid.

5. **Conclusion**:
- As \( P_{\text{atm}} \) decreases, the total pressure at the bottom of the liquid also decreases because it is dependent on \( P_{\text{atm}} \).
- Therefore, the pressure in the liquid near the bottom will decrease as the air is continuously pumped out.

### Final Answer:
The pressure in the liquid near the bottom of the beaker will **decrease** as the air inside the jar is continuously pumped out.

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