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An empty balloon weighs W(1). If air equ...

An empty balloon weighs `W_(1)`. If air equal in weight to `W` is pumped into the balloon, the weight of the balloon becomes `W_(2)`. Suppose that the density of air inside and outside the balloon is the same. Then

A

`W_2=W_1`

B

`W_2=W_1+W`

C

`W_2ltW_1+W`

D

`W_2gtW_1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the situation step by step. ### Step 1: Understand the Initial Conditions - The weight of the empty balloon is denoted as \( W_1 \). - When air equal in weight to \( W \) is pumped into the balloon, the new weight of the balloon becomes \( W_2 \). ### Step 2: Define the New Volume - When air is pumped into the balloon, the volume of the balloon changes. The volume \( V \) of the air inside the balloon can be expressed in terms of the mass of the air and its density: \[ V = \frac{\text{mass}}{\text{density}} = \frac{W/g}{\rho} \] where \( W \) is the weight of the air added, \( g \) is the acceleration due to gravity, and \( \rho \) is the density of air. ### Step 3: Calculate the Real Weight of the Balloon - The real weight of the balloon after adding the air is: \[ \text{Real Weight} = W_1 + W \] ### Step 4: Consider the Buoyancy Force - The balloon is in the atmosphere, which exerts a buoyant force \( F_B \) on it. The buoyant force is equal to the weight of the air displaced by the volume of the balloon: \[ F_B = \rho g V \] - From the previous step, we know that \( V = \frac{W}{\rho g} \), so substituting this into the buoyant force equation gives: \[ F_B = \rho g \left(\frac{W}{\rho g}\right) = W \] ### Step 5: Calculate the Apparent Weight of the Balloon - The apparent weight \( W_2 \) of the balloon (the weight we measure) is given by: \[ W_2 = \text{Real Weight} - F_B \] Substituting the values we found: \[ W_2 = (W_1 + W) - W \] Simplifying this gives: \[ W_2 = W_1 \] ### Conclusion - Therefore, we conclude that: \[ W_2 = W_1 \] - This means the apparent weight of the balloon after pumping in air equal to weight \( W \) is the same as the weight of the empty balloon. ### Final Answer The correct option is that \( W_1 = W_2 \). ---
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