Home
Class 11
PHYSICS
A load of 4.0 kg is suspended from a cei...

A load of 4.0 kg is suspended from a ceiling through a steel wire of radius 2.0 mm. Find the tensile stress developed in the wire when equilibrium is achieved. Take `g=3.1pi m/s^-2`

Text Solution

AI Generated Solution

To find the tensile stress developed in the wire when a load of 4.0 kg is suspended from it, we can follow these steps: ### Step 1: Calculate the Weight of the Load The weight (W) of the load can be calculated using the formula: \[ W = m \cdot g \] where: - \( m = 4.0 \, \text{kg} \) (mass of the load) - \( g = 3.1 \pi \, \text{m/s}^2 \) ...
Promotional Banner

Topper's Solved these Questions

  • SOME MECHANICAL PROPERTIES OF MATTER

    HC VERMA ENGLISH|Exercise Worked out Example|17 Videos

  • SOME MECHANICAL PROPERTIES OF MATTER

    HC VERMA ENGLISH|Exercise Exercises|32 Videos

  • SIMPLE HARMONIC MOTION

    HC VERMA ENGLISH|Exercise Question for short Answer|15 Videos

  • SOUND WAVES

    HC VERMA ENGLISH|Exercise All Questions|133 Videos

Similar Questions

Explore conceptually related problems

A load of 4 kg is suspended from a ceiling through a steel wire of length 2 m and radius 2 mm. It is found that the length of the wire increase by 0.032 mm as equilibrium is achieved. What would be the Young's modulus of steel ? (Take , g=3.1 pi m s^(-2) )

A load of 4.0 kg is suspended from a ceiling through a steel wire of length 20 m and radius 2.0 mm. It is found that the length of the wire increases by 0.031 mm as equilibrium is achieved. Find Young modulus of steel. Take g=3.1pims^-2

A load of 4 kg is suspended from a ceiling through a steel wire of length 20 m and radius 2 mm . It is found that the length of the wire increases by 0.031 mm , as equilibrium is achieved. If g = 3.1xxpi ms(-2) , the value of young's modulus of the material of the wire (in Nm^(-2)) is

A block of mass 4 kg is suspended from the ceiling with the help of a steel wire of radius 2mm and negligible mass. Find the stress in the wire. (g=pi^(2)) (A) 4.0xx10^(6) N//m^(2) (B) 3.14xx10^(6) N//m^(2) (C) 3xx10^(5) N//m^(2) (D) 2.0xx10^(6) N//m^(2)

When a force of 80 N is applied on a uniform steel wire, its free end elongates by 1.2 mm. Find the energy stored in the wire.

A load of mass M kg is suspended from a steel wire of length 2 m and radius 1.0 mm in Searle's apparatus experiment. The increase in length produced in the wire is 4.0 mm , Now the loads is fully immersed in a liquid of relative density 2. The relative density of the material of load is 8. The new value of increase in length of the steel wire is :

A steel wire can withstand a load up to 2940N . A load of 150 kg is suspended from a rigid support. The maximum angle through which the wire can be displaced from the mean position, so that the wire does not break when the load pass through the position of equilibrium, is

When a load of 10 kg is suspended on a metallic wire, its length increase by 2 mm. The force constant of the wire is

A block of mass 0.2 kg is suspended from the ceiling by a light string. A second block of mass 0.3 kg is suspended from the first block through another string. Find the tensions in the two strings. Take g=10 m/s^2 .

A fine steel wire of length 4 m is fixed rigidly in a heavy brass frame as ashown in figure . It is just taut at 20^(@)C . The tensile stress developed in steel wire it whole system is heated to 120^(@)C is :- ( Given alpha _("brass") = 1.8 xx 10^(-5) .^(@)C^(-1), alpha_("steel") = 1.2 xx 10^(-5) .^(@)C , Y_("steel") = 2 xx 10^(11) Nm^(-2), Y_("brass")= 1.7xx10^(7) Nm^(-2) )