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A steel wire of length 2.0 m is stretche...

A steel wire of length 2.0 m is stretched through 2.0 mm. The cross sectional area of the wire is 4.0 mm^2. Calculate the elastic potential energy stored in the wire in the stretched condition. Young modulus of steel `=2.0x10^11Nm^-2`

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To calculate the elastic potential energy stored in a stretched steel wire, we can follow these steps: ### Step 1: Understand the given data - Length of the wire (L) = 2.0 m - Extension (ΔL) = 2.0 mm = 2.0 × 10^-3 m - Cross-sectional area (A) = 4.0 mm² = 4.0 × 10^-6 m² - Young's modulus (E) = 2.0 × 10^11 N/m² ...
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