Water is kept in a beaker of radius 5.0 cm. Consider a diameter of the beaker on the surface of the water. Find the force by which the surface on one side of the diameter pulls the surface on the other side. Surface tension of water `=0.075Nm^-1`.

Explanation

To solve the problem of finding the force by which the surface on one side of the diameter pulls the surface on the other side, we can follow these steps:

### Step 1: Understand the Concept of Surface Tension
Surface tension (S) is the force per unit length acting along the surface of a liquid. It causes the liquid surface to behave like a stretched elastic membrane.

### Step 2: Identify the Given Data
- Radius of the beaker (r) = 5.0 cm = 0.05 m (convert to meters)
- Surface tension of water (S) = 0.075 N/m
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