One end of a metal wire is fixed to a ceiling and a load of 2 kg hangs from the other end. A similar wire is attached to the bottom of the load and another load of 1 kg hangs from this lower wire. Find the longitudinal strain in both wires. Area of cross section of each wire is `0.005 cm^2` and Young modulus of the metal is `2.0xx10^11 Nm^-2.` Take `g=10ms^-2`

Explanation

To solve the problem, we will calculate the longitudinal strain in both wires step by step.

### Given Data:
- Mass of the first load (m1) = 2 kg
- Mass of the second load (m2) = 1 kg
- Area of cross-section of each wire (A) = 0.005 cm² = \(0.005 \times 10^{-4} \, \text{m}^2\)
- Young's modulus of the metal (E) = \(2.0 \times 10^{11} \, \text{N/m}^2\)
- Acceleration due to gravity (g) = \(10 \, \text{m/s}^2\)
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