A wire of area of cross section `3.0mm^2` and natural length 50 cm is fixed at one end and a mas of 2.1 kg is hung from the other end. Find the elastic potential energy stored in the wire in steady state. Young modulus of the material of the wire `=1.9xx10^11Nm^-2. Take g=10ms^-2`

Explanation

To find the elastic potential energy stored in the wire in steady state, we will follow these steps:

### Step 1: Calculate the weight of the mass
The weight (W) of the mass is given by the formula:
\[ W = m \cdot g \]
where:
- \( m = 2.1 \, \text{kg} \)
- \( g = 10 \, \text{m/s}^2 \)
...