A 5.0 cm long straight piece of thread is kept on the surface of water. Find the force with which the surface on one side of the thread pulls it. Surface tension of water `=0.076Nm^-1`

Explanation

To find the force with which the surface on one side of the thread pulls it, we can use the formula for the force due to surface tension. The force \( F \) can be calculated using the formula:

\[ F = \text{Surface Tension} \times \text{Length} \]

### Step-by-Step Solution:

1. **Convert the Length of the Thread to Meters**:
- The length of the thread is given as 5.0 cm.
- To convert centimeters to meters, we use the conversion factor \( 1 \text{ cm} = 0.01 \text{ m} \).
- Therefore, \( 5.0 \text{ cm} = 5.0 \times 0.01 = 0.05 \text{ m} \).

2. **Identify the Surface Tension**:
- The surface tension of water is given as \( 0.076 \text{ N/m} \).

3. **Calculate the Force**:
- Using the formula \( F = \text{Surface Tension} \times \text{Length} \):
\[ F = 0.076 \text{ N/m} \times 0.05 \text{ m} \]
- Performing the multiplication:
\[ F = 0.0038 \text{ N} \]

4. **Express the Result in Scientific Notation**:
- The force can also be expressed in scientific notation:
\[ F = 3.8 \times 10^{-3} \text{ N} \]

### Final Answer:
The force with which the surface on one side of the thread pulls it is \( 3.8 \times 10^{-3} \text{ N} \).

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