A wave pulse passing on a string with speed of `40cms^-1` in the negative x direction has its maximum at `x=0` at `t=0`. Where will this maximum be located at `t=5s?

Explanation

To solve the problem step by step, we will analyze the motion of the wave pulse and calculate the position of its maximum at a given time.

### Step 1: Understand the given information
- The speed of the wave pulse is \( v = 40 \, \text{cm/s} \).
- The wave pulse is moving in the negative x-direction.
- At time \( t = 0 \), the maximum of the wave pulse is located at \( x = 0 \).

### Step 2: Use the formula for distance
The distance traveled by the wave pulse can be calculated using the formula:
\[ \text{Distance} = \text{Speed} \times \text{Time} \]
Here, the speed is \( 40 \, \text{cm/s} \) and the time is \( 5 \, \text{s} \).

### Step 3: Calculate the distance traveled
Substituting the values into the formula:
\[ \text{Distance} = 40 \, \text{cm/s} \times 5 \, \text{s} = 200 \, \text{cm} \]

### Step 4: Determine the direction of movement
Since the wave pulse is moving in the negative x-direction, we need to account for this direction in our final position calculation. Therefore, the position of the maximum at \( t = 5 \, \text{s} \) will be:
\[ x = -200 \, \text{cm} \]

### Step 5: Final answer
Thus, at \( t = 5 \, \text{s} \), the maximum of the wave pulse will be located at:
\[ x = -200 \, \text{cm} \]

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