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A double slilt experiment is performed w...

A double slilt experiment is performed with sodium (yellow) light of wavelength 589.3 nm and the interference pattern is observed on a screen 100 cm away. The tenth bright fringe has its centre at a distance of 12 mm from the central maximum. Find the separation betwen the slits.

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To solve the problem, we will use the formula for the position of bright fringes in a double slit experiment. The formula for the position of the nth bright fringe is given by: \[ y_n = \frac{n \lambda D}{d} \] Where: - \( y_n \) = position of the nth bright fringe from the central maximum - \( n \) = order of the bright fringe (in this case, \( n = 10 \)) - \( \lambda \) = wavelength of light (in meters) ...
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