The width of one of the two slits in a Young's double slit experiment is double of the other slit. Assuming that the amplitude of the light coming from a slit is proportional to the slit width, find the ratio of the maximum to the minimum intensity in the interference pattern.

Explanation

To solve the problem, we need to analyze the situation in a Young's double slit experiment where the widths of the slits are different. Let's break it down step by step.

### Step 1: Define the Slit Widths and Amplitudes
Let the width of slit 1 be \( w \) and the width of slit 2 be \( 2w \). According to the problem, the amplitude of light from a slit is proportional to its width. Therefore, we can define the amplitudes as follows:
- Amplitude from slit 1, \( A_1 = A \)
- Amplitude from slit 2, \( A_2 = 2A \)

### Step 2: Calculate the Intensities
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