The speed of the yellow light in a certain liquid is` 2.4 x 10 8 ms^-1`. Find the refractive index of the liquid.

Explanation

To find the refractive index of the liquid given the speed of yellow light in it, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values**:
- Speed of yellow light in the liquid (VL) = \(2.4 \times 10^8 \, \text{m/s}\)
- Speed of light in air (VA) = \(3.0 \times 10^8 \, \text{m/s}\)
- Refractive index of air (µA) = 1

2. **Understand the relationship between refractive index and speed of light**:
The refractive index (µ) of a medium is defined as:
\[ \mu = \frac{V_A}{V_L} \]
where:
- \(V_A\) is the speed of light in air,
- \(V_L\) is the speed of light in the liquid.

3. **Set up the equation for the refractive index of the liquid (µL)**:
Since we want to find the refractive index of the liquid (µL), we can express it as:
\[ \mu_L = \frac{V_A}{V_L} \cdot \mu_A \]
Substituting the known values:
\[ \mu_L = \frac{3.0 \times 10^8}{2.4 \times 10^8} \cdot 1 \]

4. **Calculate the refractive index**:
\[ \mu_L = \frac{3.0}{2.4} \]
Performing the division:
\[ \mu_L = 1.25 \]

5. **Final answer**:
The refractive index of the liquid is:
\[ \mu_L = 1.25 \]