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Light is incident from glass (mu=1.5) to...

Light is incident from glass `(mu=1.5)` to air. Sketch thevariation of the angle of deviation `delta` with angle of incident i for `0ltilt90^@`

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To solve the problem of sketching the variation of the angle of deviation (δ) with the angle of incidence (i) when light travels from glass (with a refractive index μ = 1.5) to air, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - Light travels from a denser medium (glass) to a rarer medium (air). - The refractive index of glass is μ = 1.5. - The critical angle (c) can be calculated using Snell's law. 2. **Calculate the Critical Angle**: - The critical angle (c) can be found using the formula: \[ \sin(c) = \frac{n_2}{n_1} \] where \( n_1 = 1.5 \) (glass) and \( n_2 = 1.0 \) (air). - Therefore: \[ \sin(c) = \frac{1.0}{1.5} = \frac{2}{3} \] - Thus, the critical angle \( c \) is: \[ c = \sin^{-1}\left(\frac{2}{3}\right) \approx 41.81^\circ \] 3. **Analyzing the Angle of Deviation**: - The angle of deviation (δ) is defined as: \[ \delta = r - i \] where \( r \) is the angle of refraction. - For \( i = 0^\circ \): - The light travels straight through, so \( \delta = 0^\circ \). - For \( 0 < i < c \): - The light refracts into the air, and \( \delta \) increases as \( i \) increases. - For \( i = c \): - The angle of refraction \( r = 90^\circ \), hence: \[ \delta = 90^\circ - c \approx 90^\circ - 41.81^\circ \approx 48.19^\circ \] - For \( i > c \): - Total internal reflection occurs. The angle of deviation becomes: \[ \delta = 180^\circ - 2i \] - As \( i \) increases beyond \( c \), \( \delta \) will start decreasing. 4. **Sketching the Graph**: - On the graph, plot \( i \) on the x-axis (from \( 0^\circ \) to \( 90^\circ \)) and \( \delta \) on the y-axis. - The graph starts at the origin (0,0). - As \( i \) approaches \( c \), \( \delta \) increases and reaches a maximum value of approximately \( 48.19^\circ \). - After \( c \), the graph will drop sharply as \( \delta \) decreases due to total internal reflection, continuing to decrease as \( i \) approaches \( 90^\circ \). ### Final Graph: - The graph will have two distinct sections: 1. **Increasing Section**: From \( (0,0) \) to \( (c, \delta) \). 2. **Decreasing Section**: From \( (c, \delta) \) to \( (90^\circ, \delta) \).

To solve the problem of sketching the variation of the angle of deviation (δ) with the angle of incidence (i) when light travels from glass (with a refractive index μ = 1.5) to air, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - Light travels from a denser medium (glass) to a rarer medium (air). - The refractive index of glass is μ = 1.5. - The critical angle (c) can be calculated using Snell's law. ...
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HC VERMA ENGLISH-GEOMETRICAL OPTICS-Exercises
  1. A light ray is incident normally on the face AB of a right-angled pris...

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  2. Find the maximum angle of refraction when a light ray is refracted fro...

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  3. Light is incident from glass (mu=1.5) to air. Sketch thevariation of t...

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  4. Light is incident from glass (mu = 1.50) to water (mu = 1.33) find th...

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  5. Light falls from glass (mu=1.5) to air. Find the angle of incidence fo...

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  6. A point source is placed at a depth h below the surface of water (refr...

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  7. A container contains water up to a height of 20 cm and there is a poin...

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  8. Find the angle of minimum deviation for an equilateral prism made of a...

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  9. Find the angle of deviation suffered by the light ray shown in figure....

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  10. A light ray, going through a prism with the angle of prism 60^@, is fo...

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  11. Locate the image formed by refraction in the situation shown in figure

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  12. A spherical surface of radius 30 cm separates two transparent media A ...

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  13. Figure shows a transparent hemisphere of radius 3.0 cm made of a mate...

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  14. A small object is embedded in a glass sphere (mu =1.5) of radius 5.0 c...

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  15. A biconvex thick lens is constructed with glass (mu = 1.50). Each of t...

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  16. A narrow pencil of parallel light is incident normally on a solid tran...

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  17. One end of a cylindrical glass rod (mu = 1.5) of radius 1.0 cm is roun...

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  18. A paperweight in the form of a hemisphere of radius 3.0 cm is used to ...

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  19. Find the image shift if the paperweight is inverted at its place so th...

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  20. A hemispherical portion of the surface of a solid glass sphere (mu = 1...

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