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A narrow pencil of parallel light is inc...

A narrow pencil of parallel light is incident normally on a solid transparent sphere of radius r. What should be the refractive index if the pencil is to be focussed (a) at the surface of the sphere, (b) at the centre of the sphere.

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To solve the problem, we need to determine the refractive index of a solid transparent sphere when a narrow pencil of parallel light is incident normally on its surface. We will consider two cases: (a) when the light is focused at the surface of the sphere and (b) when the light is focused at the center of the sphere. ### Given: - Radius of the sphere, \( r \) - Refractive index of air, \( \mu_1 = 1 \) - Object distance, \( u = -\infty \) (since the light rays are coming from infinity) ### Case (a): Focusing at the Surface of the Sphere 1. **Identify the Image Distance**: - Since the light is focused at the surface of the sphere, the image distance \( v = 2r \) (the distance from the center of the sphere to the surface is \( r \), and the light converges to the surface). 2. **Apply the Lens Maker's Formula**: The formula for refraction at a curved surface is given by: \[ \frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R} \] Here, \( R = r \) (the radius of the sphere). 3. **Substituting Values**: Substitute \( v = 2r \), \( u = -\infty \), and \( R = r \): \[ \frac{\mu_2}{2r} - \frac{1}{-\infty} = \frac{\mu_2 - 1}{r} \] The term \( \frac{1}{-\infty} \) becomes \( 0 \), so we have: \[ \frac{\mu_2}{2r} = \frac{\mu_2 - 1}{r} \] 4. **Simplifying the Equation**: Multiply through by \( 2r \): \[ \mu_2 = 2(\mu_2 - 1) \] Expanding gives: \[ \mu_2 = 2\mu_2 - 2 \] Rearranging leads to: \[ \mu_2 - 2\mu_2 = -2 \implies -\mu_2 = -2 \implies \mu_2 = 2 \] ### Conclusion for Case (a): The refractive index \( \mu_2 \) for the light to be focused at the surface of the sphere is \( 2 \). --- ### Case (b): Focusing at the Center of the Sphere 1. **Identify the Image Distance**: - For this case, the image is formed at the center of the sphere, so the image distance \( v = r \). 2. **Apply the Lens Maker's Formula Again**: Using the same formula: \[ \frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R} \] Substitute \( v = r \), \( u = -\infty \), and \( R = r \): \[ \frac{\mu_2}{r} - \frac{1}{-\infty} = \frac{\mu_2 - 1}{r} \] Again, the term \( \frac{1}{-\infty} \) becomes \( 0 \): \[ \frac{\mu_2}{r} = \frac{\mu_2 - 1}{r} \] 3. **Simplifying the Equation**: Multiply through by \( r \): \[ \mu_2 = \mu_2 - 1 \] Rearranging gives: \[ 0 = -1 \] This is not possible. ### Conclusion for Case (b): The equation cannot be satisfied, indicating that it is not possible for the light to be focused at the center of the sphere. --- ### Summary of Results: - (a) The refractive index \( \mu_2 \) for focusing at the surface of the sphere is \( 2 \). - (b) It is not possible to focus the light at the center of the sphere.

To solve the problem, we need to determine the refractive index of a solid transparent sphere when a narrow pencil of parallel light is incident normally on its surface. We will consider two cases: (a) when the light is focused at the surface of the sphere and (b) when the light is focused at the center of the sphere. ### Given: - Radius of the sphere, \( r \) - Refractive index of air, \( \mu_1 = 1 \) - Object distance, \( u = -\infty \) (since the light rays are coming from infinity) ### Case (a): Focusing at the Surface of the Sphere ...
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HC VERMA ENGLISH-GEOMETRICAL OPTICS-Exercises
  1. A small object is embedded in a glass sphere (mu =1.5) of radius 5.0 c...

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  2. A biconvex thick lens is constructed with glass (mu = 1.50). Each of t...

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  3. A narrow pencil of parallel light is incident normally on a solid tran...

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  4. One end of a cylindrical glass rod (mu = 1.5) of radius 1.0 cm is roun...

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  5. A paperweight in the form of a hemisphere of radius 3.0 cm is used to ...

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  6. Find the image shift if the paperweight is inverted at its place so th...

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  7. A hemispherical portion of the surface of a solid glass sphere (mu = 1...

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  8. The convex surface of a thin concave-convex lens of glass of refractiv...

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  9. A double convex lens has focal length 25 cm. The radius of curvature o...

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  10. The radii of curvature of a lens are + 20 cm and + 30 cm. The material...

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  11. Lenses are constructed by a material of refractive indeic 1'50. The ma...

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  12. A thin lens made of a material of refractive indexmu2 has a medium of ...

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  13. A convex lens has a focal length of 10 cm. Find the location and natur...

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  14. A slide projector has to project a 35 mm slide (35 mm xx 23 mm) on a 2...

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  15. A particle executes a simple harmonic motion of amplitude 1.0 cm along...

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  16. An extended object is placed at a distance of 5.0 cm from a convex len...

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  17. A pin of length 2.00 cm is placed perpendicular to the principal axis ...

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  18. A convex lens produces a double size real image when an object is plac...

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  19. A pin of length 2.0 cm lies along the principal axis of a converging l...

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  20. The diameter of the sun is 1.4 X 10^9m and its distance from the earth...

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