A sound wave of wavelength 40 cm travels in air. If the difference between the maximum and minimum pressures at a given point is `1.0xx10^-3Nm^-2`, find the amplitude of vibration of the particle o the medium. The bulk modulus of air is `1.4xx10^5Nm^-2`.

Explanation

To solve the problem step by step, we will follow the given information and apply the relevant formulas.

### Step 1: Understand the given data
- Wavelength (\( \lambda \)) = 40 cm = 0.4 m
- Difference between maximum and minimum pressures (\( \Delta P \)) = \( 1.0 \times 10^{-3} \, \text{N/m}^2 \)
- Bulk modulus of air (\( B \)) = \( 1.4 \times 10^{5} \, \text{N/m}^2 \)

### Step 2: Calculate the pressure amplitude (\( P_0 \))
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