A tuning fork vibrates at `264 Hz`. Find the length of the shortest closed organ pipe that will resonate with the tuning fork. Speed of sound in air is `350ms^-1`.

Explanation

To find the length of the shortest closed organ pipe that will resonate with a tuning fork vibrating at 264 Hz, we can follow these steps:

### Step 1: Understand the Resonance Condition
For a closed organ pipe, the resonant frequencies are given by the formula:
\[ f = \frac{(2n + 1) \cdot V}{4L} \]
where:
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