A source and a detector move away from each other, each with a speed of `10 ms^-1` with respect to the ground with no wind. If the detector detects a frequency 1950 Hz of the sound coming from the source, what is the original frequency of the source? Speed of sound in air `=340 ms^-1`.

Explanation

To find the original frequency of the sound emitted by the source, we can use the formula for the apparent frequency when both the source and the observer are moving away from each other.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Apparent frequency (\( \mu' \)) = 1950 Hz
- Speed of sound in air (\( V \)) = 340 m/s
- Speed of source (\( Us \)) = 10 m/s (moving away)
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