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An electronically driven loudspeaker is placed near the open end of a resonance column apparatus. The length of air column in the tube is 80 cm. The frequency of the loudspeaker can be varied between 20 Hz and 2 kHz. Find the frequencies at which the column will resonate. Speed of sound in air `= 320 m s^-1`

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To find the resonant frequencies of the air column in the resonance column apparatus, we can follow these steps: ### Step 1: Identify the parameters - Length of the air column (L) = 80 cm = 0.8 m - Speed of sound in air (V) = 320 m/s ### Step 2: Use the formula for the fundamental frequency of a closed organ pipe The fundamental frequency (ν₀) for a closed organ pipe is given by the formula: \[ ν₀ = \frac{V}{4L} \] ### Step 3: Calculate the fundamental frequency Substituting the values into the formula: \[ ν₀ = \frac{320 \, \text{m/s}}{4 \times 0.8 \, \text{m}} = \frac{320}{3.2} = 100 \, \text{Hz} \] ### Step 4: Determine the resonant frequencies The resonant frequencies (ν) for a closed organ pipe can be calculated using the formula: \[ ν = (2n + 1)ν₀ \] where \(n\) is a non-negative integer (0, 1, 2, ...). ### Step 5: Calculate the resonant frequencies for different values of n 1. For \(n = 0\): \[ ν_0 = (2 \times 0 + 1) \times 100 = 100 \, \text{Hz} \] 2. For \(n = 1\): \[ ν_1 = (2 \times 1 + 1) \times 100 = 300 \, \text{Hz} \] 3. For \(n = 2\): \[ ν_2 = (2 \times 2 + 1) \times 100 = 500 \, \text{Hz} \] 4. For \(n = 3\): \[ ν_3 = (2 \times 3 + 1) \times 100 = 700 \, \text{Hz} \] 5. For \(n = 4\): \[ ν_4 = (2 \times 4 + 1) \times 100 = 900 \, \text{Hz} \] 6. For \(n = 5\): \[ ν_5 = (2 \times 5 + 1) \times 100 = 1100 \, \text{Hz} \] 7. For \(n = 6\): \[ ν_6 = (2 \times 6 + 1) \times 100 = 1300 \, \text{Hz} \] 8. For \(n = 7\): \[ ν_7 = (2 \times 7 + 1) \times 100 = 1500 \, \text{Hz} \] 9. For \(n = 8\): \[ ν_8 = (2 \times 8 + 1) \times 100 = 1700 \, \text{Hz} \] 10. For \(n = 9\): \[ ν_9 = (2 \times 9 + 1) \times 100 = 1900 \, \text{Hz} \] 11. For \(n = 10\): \[ ν_{10} = (2 \times 10 + 1) \times 100 = 2100 \, \text{Hz} \quad (\text{not valid, exceeds 2 kHz}) \] ### Step 6: List the valid resonant frequencies The valid resonant frequencies within the range of 20 Hz to 2000 Hz are: - 100 Hz - 300 Hz - 500 Hz - 700 Hz - 900 Hz - 1100 Hz - 1300 Hz - 1500 Hz - 1700 Hz - 1900 Hz ### Final Answer: The frequencies at which the column will resonate are: - 100 Hz, 300 Hz, 500 Hz, 700 Hz, 900 Hz, 1100 Hz, 1300 Hz, 1500 Hz, 1700 Hz, and 1900 Hz.

To find the resonant frequencies of the air column in the resonance column apparatus, we can follow these steps: ### Step 1: Identify the parameters - Length of the air column (L) = 80 cm = 0.8 m - Speed of sound in air (V) = 320 m/s ### Step 2: Use the formula for the fundamental frequency of a closed organ pipe The fundamental frequency (ν₀) for a closed organ pipe is given by the formula: ...
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