A platinum resistance thermometer reads `0^0` and `100^0` at the ice point and boiling point of water respectively. The resistance of a platinum wire varies with Celsius temperature `theta` as `R_t = R_0 (1+alphatheta + betatheta^2)`, where `alpha = 3.8 xx 10^(-3) ^0 C^(-1)` and `beta= -5.6 xx 10^(-7) ^0 C^(-2)`. What will be the reading of this thermometer if it is placed in a liquid bath maintained at `50^0 C`?

Explanation

To solve the problem, we need to calculate the resistance of the platinum thermometer at a temperature of 50°C using the given formula for resistance and then relate it to the temperature reading.

### Step 1: Understand the Resistance Formula
The resistance of the platinum wire is given by the formula:
\[ R_t = R_0 (1 + \alpha \theta + \beta \theta^2) \]
where:
- \( R_t \) is the resistance at temperature \( \theta \),
- \( R_0 \) is the resistance at 0°C (ice point),
...