A meter scale made of steel is calibrated at `20^@C` to give correct reading. Find the distance between 50 cm mark and 51 cm mark if the scale is used at `10^@C`. Coefficient of linear expansion of steel is `1.1 xx 10^(-5)C^(-1)`

Explanation

To solve the problem, we need to find the distance between the 50 cm mark and the 51 cm mark on a steel meter scale when the temperature is reduced to 10°C. The scale was originally calibrated at 20°C. We will use the coefficient of linear expansion of steel to find the new length.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Initial temperature, \( T_1 = 20°C \)
- Final temperature, \( T_2 = 10°C \)
- Coefficient of linear expansion of steel, \( \alpha = 1.1 \times 10^{-5} \, °C^{-1} \)
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