Two meter scales, one of steel and the other of aluminum, agree at `20^@C`. Calculate the ratio aluminum-centimeter/steel-centimeter at (a) `0^@C`, (b) `40^@C` and (c) `100^@C`. `alpha_(steel) = 1.1 xx 10^(-5)C^(-1)` and `alpha_(aluminum)=2.3 xx 10^(-5)C^(-1)`.

Explanation

To solve the problem, we need to calculate the ratio of the lengths of aluminum and steel scales at three different temperatures: 0°C, 40°C, and 100°C. We will use the formula for linear expansion, which states:

\[ L' = L(1 + \alpha \Delta T) \]

Where:
- \(L'\) is the final length after expansion.
...