A steel ball initially at a pressure of `1.0 xx 10^5 Pa` is heated from `20^@ C` to `120^@ C` keeping its volume constant. Find the pressure inside the ball. Coefficient of linear expansion of steel `= 12 xx 10^(-6) C^(-1)` and bulk modulus of steel `= 1.6 xx 10^(11) N m^(-2)`

Explanation

To solve the problem, we will use the relationship between pressure, bulk modulus, and thermal expansion. Here’s the step-by-step solution:

### Step 1: Identify the given data
- Initial pressure, \( P_1 = 1.0 \times 10^5 \, \text{Pa} \)
- Initial temperature, \( T_1 = 20^\circ C \)
- Final temperature, \( T_2 = 120^\circ C \)
- Coefficient of linear expansion of steel, \( \alpha = 12 \times 10^{-6} \, \text{C}^{-1} \)
- Bulk modulus of steel, \( B = 1.6 \times 10^{11} \, \text{N/m}^2 \)
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