calculate the increase in internal energy of 1 kg of water at `100^(o)C` when it is converted into steam at the same temperature and at 1atm (100 kPa). The density of water and steam are 1000 kg `m^(-3)` and 0.6 kg `m^(-3)` respectively. The latent heat of vaporization of water `=2.25xx10^(6) J kg^(1)`.

Explanation

To calculate the increase in internal energy of 1 kg of water at 100°C when it is converted into steam at the same temperature and at 1 atm, we will follow these steps:

### Step 1: Calculate the volume of water
The volume of 1 kg of water can be calculated using the formula:
\[ V_{\text{water}} = \frac{m}{\text{density of water}} = \frac{1 \, \text{kg}}{1000 \, \text{kg/m}^3} = 0.001 \, \text{m}^3 \]

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