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The pressure p and volume V of an ideal ...

The pressure p and volume V of an ideal gas both increase in a process.

A

such a process is not possible.

B

The work done by the system is positive.

C

The tempreture of the system must increase.

D

Heat supplied to the gas is equal to the change in internal energy.

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To analyze the process where both the pressure \( P \) and volume \( V \) of an ideal gas increase, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Work Done by the Gas**: - The work done \( W \) by the gas during expansion is given by the formula: \[ W = P \Delta V \] - Here, \( \Delta V = V_f - V_i \) (final volume - initial volume). Since the volume is increasing, \( \Delta V \) is positive. **Conclusion**: The work done by the system is positive. 2. **Analyzing the Ideal Gas Law**: - The ideal gas law is expressed as: \[ PV = nRT \] - Given that both \( P \) and \( V \) are increasing, we can infer that the temperature \( T \) must also increase to satisfy the equation, assuming the number of moles \( n \) and the gas constant \( R \) remain constant. **Conclusion**: The temperature of the system must increase. 3. **Applying the First Law of Thermodynamics**: - The first law of thermodynamics states: \[ \Delta Q = \Delta W + \Delta U \] - Where \( \Delta Q \) is the heat added to the system, \( \Delta W \) is the work done by the system, and \( \Delta U \) is the change in internal energy. - Since we have established that the work done \( \Delta W \) is positive (not zero), it implies that heat supplied to the gas cannot be equal to the change in internal energy \( \Delta U \) unless the work done is zero. **Conclusion**: The heat supplied to the gas is not equal to the change in internal energy. 4. **Final Evaluation of Options**: - Based on our analysis: - **Option 1**: Incorrect (such a process is possible). - **Option 2**: Correct (the work done by the system is positive). - **Option 3**: Correct (the temperature of the system must increase). - **Option 4**: Incorrect (heat supply to the gas is not equal to the change in internal energy). ### Final Answer: The correct options are **Option 2** and **Option 3**.

To analyze the process where both the pressure \( P \) and volume \( V \) of an ideal gas increase, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Work Done by the Gas**: - The work done \( W \) by the gas during expansion is given by the formula: \[ W = P \Delta V ...
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