50 cal of heat should be supplied to take a system from the state A to the state B through the path ABC as shown in fig, Find the quantity of heat to be supplied to take it from A to B via ADB.

Answer

A, C

Explanation

In path ACB,`DeltaQ =50cal.=(50xx4*2)J`
`=`210J`,
`DeltaW=W_(AC)+W_(CB`
`=`50xx10^-3xx200xx10^-6`
`=`10Jltbrge10J`
`DeltaQ=DeltaU+DeltaW`
``rArrDeltaU=DeltaQ-DeltaQ-Delta-DeltaW=(210-10)J
200J
Inpath ADB,DeltaQ=?
DeltaU=200J
(Internal energy change between two point is always same)`
`DeltaW=W(AD)+W(DB)=DeltaWltbrge0 + 155xx10^3xx200xx10^(-6)`
` = 31J`
`Delta Q = Delta U+deltaW`
` = (200+31)J = 231J`
` = 55cal.