Two particles A and B having charges ` 8.0 xx 10 ^(-6) C` and `-2.0 xx 10(-6) C` respectively are held fixed with a. separtion of 20cm. Where should a thired charged. particle be placed so that it dose not experience a net electric force?.

Explanation

To solve the problem, we need to determine the position where a third charged particle (let's call it particle C) should be placed so that it experiences no net electric force due to the other two charged particles A and B.

### Step-by-Step Solution:

1. **Identify the Charges and Their Positions**:
- Charge A (QA) = \(8.0 \times 10^{-6} \, C\)
- Charge B (QB) = \(-2.0 \times 10^{-6} \, C\)
- The distance between A and B = 20 cm = 0.2 m.
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