A hydrogen atom contains one proton and one electron. It may be assumed that the electron revolves in a circle of radius 0.53 angstrom `(1 angstrom = 10^(-10)` m and is abbreviated as A) with the proton at the centre. The hydrogen atom is said to be in the ground state in this case. Find the magnitude of the electric force between the proton and the electron of a hydrogen atom in its ground state.

Explanation

To find the magnitude of the electric force between the proton and the electron of a hydrogen atom in its ground state, we can follow these steps:

### Step 1: Understand the parameters
- The hydrogen atom consists of one proton and one electron.
- The radius of the electron's orbit in the ground state is given as \( r = 0.53 \) angstroms, which is \( 0.53 \times 10^{-10} \) m.

### Step 2: Identify the constants
- The electrostatic force between two charges can be calculated using Coulomb's law:
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