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Two identically charged particles are fastened to the two ends of a spring of spring constant `100 N m ^(-1) ,` find the extension In the length of the spring. Assume that the extension is small as compared to the natural length . Justify this assumption after you solve the problem.

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To solve the problem of finding the extension in the length of the spring when two identically charged particles are fastened to its ends, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Forces Acting on the Spring**: The two charged particles will exert an electrostatic repulsive force on each other due to their identical charges. This force will cause the spring to extend. 2. **Use Coulomb's Law for Electrostatic Force**: ...
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HC VERMA ENGLISH-ELECTRIC FIELD AND POTENTIAL-Exercises
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  2. Two particles A and B having charges q and 2q respectively are placed ...

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  5. A particle A having a charge of 2.0xx 10^(-6) C and a mass of 100 g i...

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  6. Two particles A and B having equal charges are placed at distance d ap...

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  7. Two particles A and B , each carrying charge Q are held fixed with a s...

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  8. Two particles A and B , each carrying charge Q are held fixed with a s...

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  9. The electric force experienced by a charge of 1.0xx10^(-6) C is 1.5 xx...

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  10. Two particles A and B having charges of +2.00 xx 10^(-6) C and of - 4....

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  11. A Point charge produces an electric field in room. What is its direct...

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  14. Positive charge Q is distributed uniformly over a circular ring of rad...

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  15. A rod of length L has a total charge Q distributed uniformly along its...

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  16. A 10 cm long rod carries a charge of +150 muC distributed uniformly a...

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  17. Consider a uniformly charged ring of radius R. Find the point on the a...

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  18. A wire is bent in the form of a regular hexagon and a total charge q i...

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  19. A cjircular wire-loop of radius a carries a total charge Q distributed...

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  20. A positive charge q is placed in front of conducting solid cube at a d...

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