A particle A having a charge of `2.0xx10 ^(-6) C` is held fixed on a horizontal table. A second charged jparticle of mass 80g stays in equilibrium on the table at a distance of 10 cm from the firsst charge. The coefficient of friction between the table and this second jparticle is `mu = 0.2`. find the range within which the charge of this second particle may lie.

Explanation

To solve the problem, we need to analyze the forces acting on the second charged particle (particle B) that is in equilibrium on the table. Here are the steps to find the range of charge for particle B:

### Step 1: Identify the forces acting on particle B
- The electrostatic force (Fe) acting on particle B due to particle A.
- The frictional force (Fs) opposing the motion of particle B.

### Step 2: Write the expression for the electrostatic force
The electrostatic force between two charges is given by Coulomb's law:
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