Two particles A and B having equal charges are placed at distance d apart. A third charged particle placed on the perpendicular bisector at a distance x will experience the maximum Coulomb’s force when :

Explanation

To solve the problem, we need to determine the distance \( x \) at which a third charged particle experiences maximum Coulomb force due to two equal charges \( A \) and \( B \) placed at a distance \( d \) apart.

### Step-by-Step Solution:

1. **Understanding the Setup**:
- Let the charges at points \( A \) and \( B \) both have charge \( Q \).
- The distance between charges \( A \) and \( B \) is \( d \).
- The third charge \( q \) is placed at point \( C \) on the perpendicular bisector of \( AB \) at a distance \( x \).
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