Two particles A and B having charges of `+2.00 xx 10^(-6) C` and of `- 4.00xx 10^(-6)` respectively are held fixed at a separation of 20.0 cm . Locate the point(s) on the line AB where (a) the electric field is zero (b) the electric potential is zero.

Explanation

To solve the problem, we need to find the points along the line connecting two charges \( A \) and \( B \) where the electric field and the electric potential are both zero.

### Given:
- Charge \( A = +2.00 \times 10^{-6} \, C \) (denote as \( Q \))
- Charge \( B = -4.00 \times 10^{-6} \, C \) (denote as \( -2Q \))
- Separation between charges \( d = 20.0 \, cm = 0.2 \, m \)

### Part (a): Locating the point where the electric field is zero
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