Home
Class 12
PHYSICS
The bob of a simple pendulum has a mas...

The bob of a simple pendulum has a mass of 40 g and a positive charge of `4.0 xx 10 ^(-5) C` . It makes 20 oscillations in 45 s. A vertical electric field pointing upward and of magnitude `2.5 xx 10^ 4 NC^(-1)` is switched on. How much time will it now take to complete 20 oscillations?

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Calculate the time period of the pendulum without the electric field (T1) Given: - Mass of the bob, \( m = 40 \, \text{g} = 40 \times 10^{-3} \, \text{kg} \) - Number of oscillations = 20 - Time for 20 oscillations = 45 s ...
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC FIELD AND POTENTIAL

    HC VERMA ENGLISH|Exercise question for short answer|14 Videos
  • ELECTRIC FIELD AND POTENTIAL

    HC VERMA ENGLISH|Exercise Objective 1|9 Videos
  • ELECTRIC FIELD AND POTENTIAL

    HC VERMA ENGLISH|Exercise worked out Examples|19 Videos
  • ELECTRIC CURRENT THROUGH GASES

    HC VERMA ENGLISH|Exercise Short answer|6 Videos
  • ELECTROMAGNETIC INDUCTION

    HC VERMA ENGLISH|Exercise Questions for short answer|9 Videos

Similar Questions

Explore conceptually related problems

A bob of a simple pendulum of mass 40 mg with a positive charge 4 xx 10^(-6) C is oscilliating with time period "T_(1). An electric field of intensity 3.6 xx 10^(4) N/c is applied vertically upwards now time period is T_(2) . The value of (T_(2))/(T_(1)) is (g = 10 m/s^(2))

A pendulum bob of mass 80mg and carrying a charge of 2xx 10^(-8)C is at rest in a uniform, horizontal electric field of 20k Vm^-1. Find the tension in the thread.

A vertical electric field of magnitude 4.00xx 10^5 NC^(-1) . just prevents a water droplet of mass 1.000xx10^(-4) kg from. falling., find the charge on the droplet.

The bob of a simple pendulum has mass 2g and a charge of 5.0muC . It is at rest in a uniform horizontal electric field of intensity 2000V//m . At equilibrium, the angle that the pendulum makes with the vertical is: (take g=10m//s^(2) )

The bob of a simple pendulum has mass 2g and a charge of 5.0muC . It is at rest in a uniform horizontal electric field of intensity 200V//m . At equilibrium, the angle that the pendulum makes with the vertical is: (take g=10m//s^(2) )

A particle of mass m and charge q is oscillating simple harmonically from a string of length l .Now a vertical electric field of magnitude E = (mg)/(2q) is switched on.The ration of new time period to old time period is

Find the magnitude of the electric field at a point 4 cm away from a line charge of density 2 xx 10^(-6) C m^(-1) .

A charged particle of mass 5 xx 10^(-5) kg is held stationary in space by placing it in an electric field of strength 10^(7) NC^(-1) directed vertically downwards. The charge on the particle is

A magnetic dipole of magnetic moment 6xx 10^(-2) A m^2 and moment of inertia 12 xx 10^(-6) kg m^2 performs oscillations in a magnetic field of 2 xx 10^(-2) T. The time taken by the dipole to complete 20 oscillations is (pi~~3)

A first order reaction has a specific reaction rate of 10^(-2) s^(-1) . How much time will it take for 20 g of the reactant to reduce to 5 g ?

HC VERMA ENGLISH-ELECTRIC FIELD AND POTENTIAL-Exercises
  1. A particle of mass 1 g and charge 2. 5 xx10^(-4) C is released from re...

    Text Solution

    |

  2. A ball of mass 100g and having a charge of 4.9xx 10^(-5) C is released...

    Text Solution

    |

  3. The bob of a simple pendulum has a mass of 40 g and a positive char...

    Text Solution

    |

  4. A block of mass m having a charge q is placed on a smooth horizontal t...

    Text Solution

    |

  5. A block of mass m containing a net positive charge q is placed on a sm...

    Text Solution

    |

  6. A Uniform electric field of 10NC ^(-1) exists in the vertically downwa...

    Text Solution

    |

  7. 12 j of work has to be done against an existion electric field to take...

    Text Solution

    |

  8. Two equal charges, 2.0xx10^(-7) C each, are held fixed at a separation...

    Text Solution

    |

  9. An electric field of 20 N//C exists along the x-axis in space. Calcula...

    Text Solution

    |

  10. Consider the situation of the previous problem. A charge of 2.0xx 10 ^...

    Text Solution

    |

  11. An electric field vecE = vec(i20 + vecj30 ) NC^(-1) exists in the spac...

    Text Solution

    |

  12. An electric field vecE = vec I Ax exists in the space, where A= 10 V ...

    Text Solution

    |

  13. The electric potential existing in space is V(x,y,z)= A (xy+ yz+zx).(a...

    Text Solution

    |

  14. Two charged particles, having equal charges of 2.0xx 10^(-5) C each, a...

    Text Solution

    |

  15. Some equipotential surfaces are shown in figure(29.E3) What can you sa...

    Text Solution

    |

  16. Consider a circular ring of radius r, uniformly charged with linear ch...

    Text Solution

    |

  17. An electric field of magnitude 1000 NC ^(-1) is produced between two p...

    Text Solution

    |

  18. A uniform field of 2.0 NC^(-1) exists in space in x direction (a) Taki...

    Text Solution

    |

  19. How much work has to be done in assembling three charged particles at ...

    Text Solution

    |

  20. The kinetc energy of a chargd particle decreased by 10 J as it moves f...

    Text Solution

    |