Two equal charges, `2.0xx10^(-7) C` each, are held fixed at a separation of 20cm. A third charge of equal magnitude is placed midway between the two both the charges. How much work is done by the electric field during the process?

Explanation

To solve the problem, we need to calculate the work done by the electric field when a third charge is placed midway between two equal charges. Let's break it down step by step.

### Step 1: Identify the Initial Configuration
We have two fixed charges, \( q_1 = q_2 = 2.0 \times 10^{-7} \, \text{C} \), separated by a distance \( R = 20 \, \text{cm} = 0.2 \, \text{m} \).

### Step 2: Calculate the Initial Potential Energy (E_initial)
In the initial configuration, there are only two charges, and the potential energy \( E_{\text{initial}} \) between them is given by:
\[
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