An electric field `vecE = vec(i20 + vecj30 ) NC^(-1)` exists in the space. If the potential at the origin is taken to be zero find the potential at (2m, 2m).

Explanation

To find the electric potential at the point (2m, 2m) given the electric field \(\vec{E} = 20 \hat{i} + 30 \hat{j} \, \text{N/C}\) and that the potential at the origin is zero, we can follow these steps:

### Step 1: Understand the relationship between electric field and potential
The electric potential \(V\) at a point in an electric field can be calculated using the formula:
\[ V = V_0 - \int_{\text{path}} \vec{E} \cdot d\vec{r} \]
where \(V_0\) is the potential at the starting point (in this case, the origin), \(\vec{E}\) is the electric field, and \(d\vec{r}\) is the differential displacement vector along the path.
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