Two identical particles, each having a charge of `2.0xx10^(-4) C` and mass of 10g, are kept at a separation of 10cm and then released. What would be the speeds of the particles when the separation becomes large?

Explanation

To solve the problem, we will use the principle of conservation of energy. The initial potential energy of the system will be converted into kinetic energy when the particles are far apart.

### Step 1: Identify the given values
- Charge of each particle, \( q = 2.0 \times 10^{-4} \, \text{C} \)
- Mass of each particle, \( m = 10 \, \text{g} = 10 \times 10^{-3} \, \text{kg} = 0.01 \, \text{kg} \)
- Initial separation, \( r = 10 \, \text{cm} = 10 \times 10^{-2} \, \text{m} = 0.1 \, \text{m} \)

### Step 2: Calculate the initial potential energy
...