When `1.0 xx 10^12`electrons are transferred from one conductor to another, a potential difference of `10 V` . What will be capacitance of the two -conductor system .

Explanation

To find the capacitance of the two-conductor system when `1.0 × 10^12` electrons are transferred and a potential difference of `10 V` is established, we can follow these steps:

### Step 1: Calculate the total charge (Q) transferred
The total charge transferred can be calculated using the formula:
\[ Q = n \cdot e \]
where:
- \( n \) is the number of electrons transferred, which is \( 1.0 \times 10^{12} \).
- \( e \) is the charge of a single electron, approximately \( 1.6 \times 10^{-19} \) coulombs.
...