The plate of a capacitor are 2.00cm apart . An electron -proton pair is released somewhere in the gap between the plates and it is found that the proton reaches the negative plate . At what distance from the negative plate was the pair released?

Explanation

To solve the problem of finding the distance from the negative plate at which the electron-proton pair was released, we can follow these steps:

### Step 1: Understand the Setup
The plates of the capacitor are 2.00 cm apart. We denote the distance from the negative plate to the point where the pair is released as \( x \). Therefore, the distance from the positive plate to the point of release will be \( 2.00 \, \text{cm} - x \).

### Step 2: Identify the Forces Acting on the Particles
The proton is positively charged and will move towards the negative plate, while the electron, being negatively charged, will move towards the positive plate. Both particles experience forces due to the electric field \( E \) between the plates.

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