A charge of` +2.0xx 10 ^-8 C` is placed on the positive plate and a charge of -2.0x10 ^-8 C at negative plate. And capacitance of capacitor is 1.2 x (10^-3) mu F. Calculate the potential difference developed between the plates.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Given Data
We have:
- Charge on the positive plate, \( Q = +2.0 \times 10^{-8} \, \text{C} \)
- Charge on the negative plate, \( Q = -2.0 \times 10^{-8} \, \text{C} \) (the magnitude is the same)
- Capacitance of the capacitor, \( C = 1.2 \times 10^{-3} \, \mu \text{F} \)

...