Two capacitors of capacitances `20 .0pF` and `50.0pF ` are connected in series with a `6.00V bettery . Find (a )the potential difference across each capacitor and (b) the energy stored in each capacitor .

Explanation

To solve the problem step by step, we will first find the equivalent capacitance of the capacitors in series, then calculate the charge, the potential difference across each capacitor, and finally the energy stored in each capacitor.

### Step 1: Calculate the Equivalent Capacitance
For capacitors in series, the formula for the equivalent capacitance \( C \) is given by:

\[ \frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_2} \]
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