Two capacitor of capacitance `4.0muF `and `6.0muF' are connected in series with a battery of 20 V . Find the energy supplied by the battery .

Explanation

To solve the problem step by step, we will follow these instructions:

### Step 1: Identify the given values
We have two capacitors connected in series:
- Capacitance of Capacitor 1, \( C_1 = 4.0 \, \mu F = 4.0 \times 10^{-6} \, F \)
- Capacitance of Capacitor 2, \( C_2 = 6.0 \, \mu F = 6.0 \times 10^{-6} \, F \)
- Voltage of the battery, \( V = 20 \, V \)

...