A paller- plate capacitor has plate area `100cm^2` and plate separation 1.0cm.A glass plate (dielectric constant 4.0)are inserted one over the other the fill the space between the plate of the capacitor.Find the new capacitance.

Explanation

To find the new capacitance of the parallel plate capacitor after inserting a glass plate with a dielectric constant, we can follow these steps:

### Step 1: Convert the given values into SI units
- The area \( A \) of the plates is given as \( 100 \, \text{cm}^2 \).
\[ A = 100 \, \text{cm}^2 = 100 \times 10^{-4} \, \text{m}^2 = 10^{-2} \, \text{m}^2 \]
- The separation \( D \) between the plates is given as \( 1.0 \, \text{cm} \).
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