An electorn beam has an aperture `1.0 mm^(2)`. A totak of `6.0xx10^(16)` electons go through any perpendicular cross section per second. Find(a) the current and (b) the current density in the beam.

Explanation

To solve the problem, we will follow a step-by-step approach to find the current and the current density of the electron beam.

### Given Data:
- Area of the aperture, \( A = 1.0 \, \text{mm}^2 = 1.0 \times 10^{-6} \, \text{m}^2 \) (conversion to SI units)
- Number of electrons passing through per second, \( n = 6.0 \times 10^{16} \, \text{electrons/s} \)
- Charge of an electron, \( e = 1.6 \times 10^{-19} \, \text{C} \)

### (a) Finding the Current (I)
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