The plates of a `50(mu)F` capacitor charged to `400(mu)C` are connected through a resistance of `1.0k(ohm)`. Find the charge remaining on the capacitor 1s after the connection is made.

Explanation

To solve the problem step by step, we will use the formula for the charge remaining on a capacitor after a certain time when it is connected through a resistor.

### Step 1: Identify the given values
- Initial charge on the capacitor, \( Q_0 = 400 \, \mu C = 400 \times 10^{-6} \, C \)
- Capacitance of the capacitor, \( C = 50 \, \mu F = 50 \times 10^{-6} \, F \)
- Resistance, \( R = 1.0 \, k\Omega = 1000 \, \Omega \)
- Time, \( t = 1 \, s \)

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