A parallel-plate capacitor has plates of area `10cm^(2)` separated by a distance of 1mm. It is filled with the dielectric mica and connected to a battery of emf 6 volts. Find the leakage current through the capacitor. Resistivity of mica`=1xx10^(13)(Omega)m`.

Explanation

To find the leakage current through the capacitor filled with mica, we can follow these steps:

### Step 1: Convert the given values into SI units.
- The area of the plates \( A = 10 \, \text{cm}^2 = 10 \times 10^{-4} \, \text{m}^2 = 10^{-3} \, \text{m}^2 \).
- The distance between the plates \( D = 1 \, \text{mm} = 1 \times 10^{-3} \, \text{m} \).
- The emf of the battery \( E = 6 \, \text{V} \).
- The resistivity of mica \( \rho = 1 \times 10^{13} \, \Omega \cdot \text{m} \).

...