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A battery of emf 2.0 V and internal resi...

A battery of emf `2.0 V` and internal resistance `0.10 Omega` is being charged with a current of `5.0 A`. Find the potential difference between the terminals of the battery?

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As the battery is being charged,the current goes into the positive terminal as shown in figure.
The potential drop across the intermal resistance is
`5.0Axx0.10(Omega)=0.50V.`
Hence ,the potential dorp across the terminals will be
`2.0V+0.50V=2.5V.`
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HC VERMA ENGLISH-ELECTRIC CURRENT IN CONDUCTORS-worked out Example
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